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Solution - Absolute value equations

Exact form: x=-37,-1123
x=-\frac{3}{7} , -\frac{11}{23}
Decimal form: x=0.429,0.478
x=-0.429 , -0.478

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|15x+7|=|8x+4|
without the absolute value bars:

|x|=|y||15x+7|=|8x+4|
x=+y(15x+7)=(8x+4)
x=y(15x+7)=(8x+4)
+x=y(15x+7)=(8x+4)
x=y(15x+7)=(8x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||15x+7|=|8x+4|
x=+y , +x=y(15x+7)=(8x+4)
x=y , x=y(15x+7)=(8x+4)

2. Solve the two equations for x

9 additional steps

(15x+7)=(8x+4)

Subtract from both sides:

(15x+7)-8x=(8x+4)-8x

Group like terms:

(15x-8x)+7=(8x+4)-8x

Simplify the arithmetic:

7x+7=(8x+4)-8x

Group like terms:

7x+7=(8x-8x)+4

Simplify the arithmetic:

7x+7=4

Subtract from both sides:

(7x+7)-7=4-7

Simplify the arithmetic:

7x=47

Simplify the arithmetic:

7x=3

Divide both sides by :

(7x)7=-37

Simplify the fraction:

x=-37

10 additional steps

(15x+7)=-(8x+4)

Expand the parentheses:

(15x+7)=-8x-4

Add to both sides:

(15x+7)+8x=(-8x-4)+8x

Group like terms:

(15x+8x)+7=(-8x-4)+8x

Simplify the arithmetic:

23x+7=(-8x-4)+8x

Group like terms:

23x+7=(-8x+8x)-4

Simplify the arithmetic:

23x+7=4

Subtract from both sides:

(23x+7)-7=-4-7

Simplify the arithmetic:

23x=47

Simplify the arithmetic:

23x=11

Divide both sides by :

(23x)23=-1123

Simplify the fraction:

x=-1123

3. List the solutions

x=-37,-1123
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|15x+7|
y=|8x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.