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Solution - Absolute value equations

Exact form: x=17,29
x=\frac{1}{7} , 29
Decimal form: x=0.143,29
x=0.143 , 29

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4x+15|=|3x+14|
without the absolute value bars:

|x|=|y||4x+15|=|3x+14|
x=+y(4x+15)=(3x+14)
x=y(4x+15)=(3x+14)
+x=y(4x+15)=(3x+14)
x=y(4x+15)=(3x+14)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4x+15|=|3x+14|
x=+y , +x=y(4x+15)=(3x+14)
x=y , x=y(4x+15)=(3x+14)

2. Solve the two equations for x

11 additional steps

(-4x+15)=(3x+14)

Subtract from both sides:

(-4x+15)-3x=(3x+14)-3x

Group like terms:

(-4x-3x)+15=(3x+14)-3x

Simplify the arithmetic:

-7x+15=(3x+14)-3x

Group like terms:

-7x+15=(3x-3x)+14

Simplify the arithmetic:

7x+15=14

Subtract from both sides:

(-7x+15)-15=14-15

Simplify the arithmetic:

7x=1415

Simplify the arithmetic:

7x=1

Divide both sides by :

(-7x)-7=-1-7

Cancel out the negatives:

7x7=-1-7

Simplify the fraction:

x=-1-7

Cancel out the negatives:

x=17

11 additional steps

(-4x+15)=-(3x+14)

Expand the parentheses:

(-4x+15)=-3x-14

Add to both sides:

(-4x+15)+3x=(-3x-14)+3x

Group like terms:

(-4x+3x)+15=(-3x-14)+3x

Simplify the arithmetic:

-x+15=(-3x-14)+3x

Group like terms:

-x+15=(-3x+3x)-14

Simplify the arithmetic:

x+15=14

Subtract from both sides:

(-x+15)-15=-14-15

Simplify the arithmetic:

x=1415

Simplify the arithmetic:

x=29

Multiply both sides by :

-x·-1=-29·-1

Remove the one(s):

x=-29·-1

Simplify the arithmetic:

x=29

3. List the solutions

x=17,29
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4x+15|
y=|3x+14|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.