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Solution - Absolute value equations

Exact form: x=13,-57
x=\frac{1}{3} , -\frac{5}{7}
Decimal form: x=0.333,0.714
x=0.333 , -0.714

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|12x+7|=|9x+8|
without the absolute value bars:

|x|=|y||12x+7|=|9x+8|
x=+y(12x+7)=(9x+8)
x=y(12x+7)=(9x+8)
+x=y(12x+7)=(9x+8)
x=y(12x+7)=(9x+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||12x+7|=|9x+8|
x=+y , +x=y(12x+7)=(9x+8)
x=y , x=y(12x+7)=(9x+8)

2. Solve the two equations for x

9 additional steps

(12x+7)=(9x+8)

Subtract from both sides:

(12x+7)-9x=(9x+8)-9x

Group like terms:

(12x-9x)+7=(9x+8)-9x

Simplify the arithmetic:

3x+7=(9x+8)-9x

Group like terms:

3x+7=(9x-9x)+8

Simplify the arithmetic:

3x+7=8

Subtract from both sides:

(3x+7)-7=8-7

Simplify the arithmetic:

3x=87

Simplify the arithmetic:

3x=1

Divide both sides by :

(3x)3=13

Simplify the fraction:

x=13

12 additional steps

(12x+7)=-(9x+8)

Expand the parentheses:

(12x+7)=-9x-8

Add to both sides:

(12x+7)+9x=(-9x-8)+9x

Group like terms:

(12x+9x)+7=(-9x-8)+9x

Simplify the arithmetic:

21x+7=(-9x-8)+9x

Group like terms:

21x+7=(-9x+9x)-8

Simplify the arithmetic:

21x+7=8

Subtract from both sides:

(21x+7)-7=-8-7

Simplify the arithmetic:

21x=87

Simplify the arithmetic:

21x=15

Divide both sides by :

(21x)21=-1521

Simplify the fraction:

x=-1521

Find the greatest common factor of the numerator and denominator:

x=(-5·3)(7·3)

Factor out and cancel the greatest common factor:

x=-57

3. List the solutions

x=13,-57
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|12x+7|
y=|9x+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.