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Solution - Absolute value equations

Exact form:

x = \frac{11}{127}, - \frac{11}{123}

x=\frac{11}{127} , -\frac{11}{123}

Decimal form:

x = 0.087, - 0.089

x=0.087 , -0.089

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| 125 x | = | - 2 x + 11 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| 125 x \| = \| - 2 x + 11 \|$
$x = + y$	$(125 x) = (- 2 x + 11)$
$x = - y$	$(125 x) = - (- 2 x + 11)$
$+ x = y$	$(125 x) = (- 2 x + 11)$
$- x = y$	$- (125 x) = (- 2 x + 11)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| 125 x \| = \| - 2 x + 11 \|$
$x = + y$ , $+ x = y$	$(125 x) = (- 2 x + 11)$
$x = - y$ , $- x = y$	$(125 x) = - (- 2 x + 11)$

2. Solve the two equations for x

5 additional steps

$125 x = (- 2 x + 11)$

Add to both sides:

$(125 x) + 2 x = (- 2 x + 11) + 2 x$

Simplify the arithmetic:

$127 x = (- 2 x + 11) + 2 x$

Group like terms:

$127 x = (- 2 x + 2 x) + 11$

Simplify the arithmetic:

$127 x = 11$

Divide both sides by :

$\frac{(127 x)}{127} = \frac{11}{127}$

Simplify the fraction:

$x = \frac{11}{127}$

6 additional steps

$125 x = - (- 2 x + 11)$

Expand the parentheses:

$125 x = 2 x - 11$

Subtract from both sides:

$(125 x) - 2 x = (2 x - 11) - 2 x$

Simplify the arithmetic:

$123 x = (2 x - 11) - 2 x$

Group like terms:

$123 x = (2 x - 2 x) - 11$

Simplify the arithmetic:

$123 x = - 11$

Divide both sides by :

$\frac{(123 x)}{123} = \frac{- 11}{123}$

Simplify the fraction:

$x = \frac{- 11}{123}$

3. List the solutions

$x = \frac{11}{127}, - \frac{11}{123}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | 125 x |$
$y = | - 2 x + 11 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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