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Solution - Absolute value equations

Exact form: x=625,185
x=\frac{6}{25} , \frac{18}{5}
Mixed number form: x=625,335
x=\frac{6}{25} , 3\frac{3}{5}
Decimal form: x=0.24,3.6
x=0.24 , 3.6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|15x+12|=|10x+6|
without the absolute value bars:

|x|=|y||15x+12|=|10x+6|
x=+y(15x+12)=(10x+6)
x=y(15x+12)=(10x+6)
+x=y(15x+12)=(10x+6)
x=y(15x+12)=(10x+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||15x+12|=|10x+6|
x=+y , +x=y(15x+12)=(10x+6)
x=y , x=y(15x+12)=(10x+6)

2. Solve the two equations for x

11 additional steps

(-15x+12)=(10x+6)

Subtract from both sides:

(-15x+12)-10x=(10x+6)-10x

Group like terms:

(-15x-10x)+12=(10x+6)-10x

Simplify the arithmetic:

-25x+12=(10x+6)-10x

Group like terms:

-25x+12=(10x-10x)+6

Simplify the arithmetic:

25x+12=6

Subtract from both sides:

(-25x+12)-12=6-12

Simplify the arithmetic:

25x=612

Simplify the arithmetic:

25x=6

Divide both sides by :

(-25x)-25=-6-25

Cancel out the negatives:

25x25=-6-25

Simplify the fraction:

x=-6-25

Cancel out the negatives:

x=625

12 additional steps

(-15x+12)=-(10x+6)

Expand the parentheses:

(-15x+12)=-10x-6

Add to both sides:

(-15x+12)+10x=(-10x-6)+10x

Group like terms:

(-15x+10x)+12=(-10x-6)+10x

Simplify the arithmetic:

-5x+12=(-10x-6)+10x

Group like terms:

-5x+12=(-10x+10x)-6

Simplify the arithmetic:

5x+12=6

Subtract from both sides:

(-5x+12)-12=-6-12

Simplify the arithmetic:

5x=612

Simplify the arithmetic:

5x=18

Divide both sides by :

(-5x)-5=-18-5

Cancel out the negatives:

5x5=-18-5

Simplify the fraction:

x=-18-5

Cancel out the negatives:

x=185

3. List the solutions

x=625,185
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|15x+12|
y=|10x+6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.