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Solution - Absolute value equations

Exact form: x=-17,-233
x=-\frac{1}{7} , -\frac{23}{3}
Mixed number form: x=-17,-723
x=-\frac{1}{7} , -7\frac{2}{3}
Decimal form: x=0.143,7.667
x=-0.143 , -7.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+12|=|2x+11|
without the absolute value bars:

|x|=|y||5x+12|=|2x+11|
x=+y(5x+12)=(2x+11)
x=y(5x+12)=(2x+11)
+x=y(5x+12)=(2x+11)
x=y(5x+12)=(2x+11)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+12|=|2x+11|
x=+y , +x=y(5x+12)=(2x+11)
x=y , x=y(5x+12)=(2x+11)

2. Solve the two equations for x

9 additional steps

(5x+12)=(-2x+11)

Add to both sides:

(5x+12)+2x=(-2x+11)+2x

Group like terms:

(5x+2x)+12=(-2x+11)+2x

Simplify the arithmetic:

7x+12=(-2x+11)+2x

Group like terms:

7x+12=(-2x+2x)+11

Simplify the arithmetic:

7x+12=11

Subtract from both sides:

(7x+12)-12=11-12

Simplify the arithmetic:

7x=1112

Simplify the arithmetic:

7x=1

Divide both sides by :

(7x)7=-17

Simplify the fraction:

x=-17

10 additional steps

(5x+12)=-(-2x+11)

Expand the parentheses:

(5x+12)=2x-11

Subtract from both sides:

(5x+12)-2x=(2x-11)-2x

Group like terms:

(5x-2x)+12=(2x-11)-2x

Simplify the arithmetic:

3x+12=(2x-11)-2x

Group like terms:

3x+12=(2x-2x)-11

Simplify the arithmetic:

3x+12=11

Subtract from both sides:

(3x+12)-12=-11-12

Simplify the arithmetic:

3x=1112

Simplify the arithmetic:

3x=23

Divide both sides by :

(3x)3=-233

Simplify the fraction:

x=-233

3. List the solutions

x=-17,-233
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+12|
y=|2x+11|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.