Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=2,19
x=2 , \frac{1}{9}
Decimal form: x=2,0.111
x=2 , 0.111

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|10x3|=|8x+1|
without the absolute value bars:

|x|=|y||10x3|=|8x+1|
x=+y(10x3)=(8x+1)
x=y(10x3)=(8x+1)
+x=y(10x3)=(8x+1)
x=y(10x3)=(8x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||10x3|=|8x+1|
x=+y , +x=y(10x3)=(8x+1)
x=y , x=y(10x3)=(8x+1)

2. Solve the two equations for x

11 additional steps

(10x-3)=(8x+1)

Subtract from both sides:

(10x-3)-8x=(8x+1)-8x

Group like terms:

(10x-8x)-3=(8x+1)-8x

Simplify the arithmetic:

2x-3=(8x+1)-8x

Group like terms:

2x-3=(8x-8x)+1

Simplify the arithmetic:

2x3=1

Add to both sides:

(2x-3)+3=1+3

Simplify the arithmetic:

2x=1+3

Simplify the arithmetic:

2x=4

Divide both sides by :

(2x)2=42

Simplify the fraction:

x=42

Find the greatest common factor of the numerator and denominator:

x=(2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

12 additional steps

(10x-3)=-(8x+1)

Expand the parentheses:

(10x-3)=-8x-1

Add to both sides:

(10x-3)+8x=(-8x-1)+8x

Group like terms:

(10x+8x)-3=(-8x-1)+8x

Simplify the arithmetic:

18x-3=(-8x-1)+8x

Group like terms:

18x-3=(-8x+8x)-1

Simplify the arithmetic:

18x3=1

Add to both sides:

(18x-3)+3=-1+3

Simplify the arithmetic:

18x=1+3

Simplify the arithmetic:

18x=2

Divide both sides by :

(18x)18=218

Simplify the fraction:

x=218

Find the greatest common factor of the numerator and denominator:

x=(1·2)(9·2)

Factor out and cancel the greatest common factor:

x=19

3. List the solutions

x=2,19
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|10x3|
y=|8x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.