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Solution - Absolute value equations

Exact form: x=265,1415
x=\frac{26}{5} , \frac{14}{15}
Mixed number form: x=515,1415
x=5\frac{1}{5} , \frac{14}{15}
Decimal form: x=5.2,0.933
x=5.2 , 0.933

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|10x20|=|5x+6|
without the absolute value bars:

|x|=|y||10x20|=|5x+6|
x=+y(10x20)=(5x+6)
x=y(10x20)=(5x+6)
+x=y(10x20)=(5x+6)
x=y(10x20)=(5x+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||10x20|=|5x+6|
x=+y , +x=y(10x20)=(5x+6)
x=y , x=y(10x20)=(5x+6)

2. Solve the two equations for x

9 additional steps

(10x-20)=(5x+6)

Subtract from both sides:

(10x-20)-5x=(5x+6)-5x

Group like terms:

(10x-5x)-20=(5x+6)-5x

Simplify the arithmetic:

5x-20=(5x+6)-5x

Group like terms:

5x-20=(5x-5x)+6

Simplify the arithmetic:

5x20=6

Add to both sides:

(5x-20)+20=6+20

Simplify the arithmetic:

5x=6+20

Simplify the arithmetic:

5x=26

Divide both sides by :

(5x)5=265

Simplify the fraction:

x=265

10 additional steps

(10x-20)=-(5x+6)

Expand the parentheses:

(10x-20)=-5x-6

Add to both sides:

(10x-20)+5x=(-5x-6)+5x

Group like terms:

(10x+5x)-20=(-5x-6)+5x

Simplify the arithmetic:

15x-20=(-5x-6)+5x

Group like terms:

15x-20=(-5x+5x)-6

Simplify the arithmetic:

15x20=6

Add to both sides:

(15x-20)+20=-6+20

Simplify the arithmetic:

15x=6+20

Simplify the arithmetic:

15x=14

Divide both sides by :

(15x)15=1415

Simplify the fraction:

x=1415

3. List the solutions

x=265,1415
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|10x20|
y=|5x+6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.