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Solution - Absolute value equations

Exact form: x=283,217
x=\frac{28}{3} , \frac{2}{17}
Mixed number form: x=913,217
x=9\frac{1}{3} , \frac{2}{17}
Decimal form: x=9.333,0.118
x=9.333 , 0.118

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|10x15|=|7x+13|
without the absolute value bars:

|x|=|y||10x15|=|7x+13|
x=+y(10x15)=(7x+13)
x=y(10x15)=(7x+13)
+x=y(10x15)=(7x+13)
x=y(10x15)=(7x+13)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||10x15|=|7x+13|
x=+y , +x=y(10x15)=(7x+13)
x=y , x=y(10x15)=(7x+13)

2. Solve the two equations for x

9 additional steps

(10x-15)=(7x+13)

Subtract from both sides:

(10x-15)-7x=(7x+13)-7x

Group like terms:

(10x-7x)-15=(7x+13)-7x

Simplify the arithmetic:

3x-15=(7x+13)-7x

Group like terms:

3x-15=(7x-7x)+13

Simplify the arithmetic:

3x15=13

Add to both sides:

(3x-15)+15=13+15

Simplify the arithmetic:

3x=13+15

Simplify the arithmetic:

3x=28

Divide both sides by :

(3x)3=283

Simplify the fraction:

x=283

10 additional steps

(10x-15)=-(7x+13)

Expand the parentheses:

(10x-15)=-7x-13

Add to both sides:

(10x-15)+7x=(-7x-13)+7x

Group like terms:

(10x+7x)-15=(-7x-13)+7x

Simplify the arithmetic:

17x-15=(-7x-13)+7x

Group like terms:

17x-15=(-7x+7x)-13

Simplify the arithmetic:

17x15=13

Add to both sides:

(17x-15)+15=-13+15

Simplify the arithmetic:

17x=13+15

Simplify the arithmetic:

17x=2

Divide both sides by :

(17x)17=217

Simplify the fraction:

x=217

3. List the solutions

x=283,217
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|10x15|
y=|7x+13|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.