Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=-2,1811
x=-2 , \frac{18}{11}
Mixed number form: x=-2,1711
x=-2 , 1\frac{7}{11}
Decimal form: x=2,1.636
x=-2 , 1.636

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|10x|=|x18|
without the absolute value bars:

|x|=|y||10x|=|x18|
x=+y(10x)=(x18)
x=y(10x)=(x18)
+x=y(10x)=(x18)
x=y(10x)=(x18)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||10x|=|x18|
x=+y , +x=y(10x)=(x18)
x=y , x=y(10x)=(x18)

2. Solve the two equations for x

7 additional steps

10x=(x-18)

Subtract from both sides:

(10x)-x=(x-18)-x

Simplify the arithmetic:

9x=(x-18)-x

Group like terms:

9x=(x-x)-18

Simplify the arithmetic:

9x=18

Divide both sides by :

(9x)9=-189

Simplify the fraction:

x=-189

Find the greatest common factor of the numerator and denominator:

x=(-2·9)(1·9)

Factor out and cancel the greatest common factor:

x=2

6 additional steps

10x=-(x-18)

Expand the parentheses:

10x=x+18

Add to both sides:

(10x)+x=(-x+18)+x

Simplify the arithmetic:

11x=(-x+18)+x

Group like terms:

11x=(-x+x)+18

Simplify the arithmetic:

11x=18

Divide both sides by :

(11x)11=1811

Simplify the fraction:

x=1811

3. List the solutions

x=-2,1811
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|10x|
y=|x18|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.