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Solution - Absolute value equations

Exact form: x=-23,211
x=-\frac{2}{3} , \frac{2}{11}
Decimal form: x=0.667,0.182
x=-0.667 , 0.182

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|10x+2|=|x4|
without the absolute value bars:

|x|=|y||10x+2|=|x4|
x=+y(10x+2)=(x4)
x=y(10x+2)=(x4)
+x=y(10x+2)=(x4)
x=y(10x+2)=(x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||10x+2|=|x4|
x=+y , +x=y(10x+2)=(x4)
x=y , x=y(10x+2)=(x4)

2. Solve the two equations for x

11 additional steps

(10x+2)=(x-4)

Subtract from both sides:

(10x+2)-x=(x-4)-x

Group like terms:

(10x-x)+2=(x-4)-x

Simplify the arithmetic:

9x+2=(x-4)-x

Group like terms:

9x+2=(x-x)-4

Simplify the arithmetic:

9x+2=4

Subtract from both sides:

(9x+2)-2=-4-2

Simplify the arithmetic:

9x=42

Simplify the arithmetic:

9x=6

Divide both sides by :

(9x)9=-69

Simplify the fraction:

x=-69

Find the greatest common factor of the numerator and denominator:

x=(-2·3)(3·3)

Factor out and cancel the greatest common factor:

x=-23

10 additional steps

(10x+2)=-(x-4)

Expand the parentheses:

(10x+2)=-x+4

Add to both sides:

(10x+2)+x=(-x+4)+x

Group like terms:

(10x+x)+2=(-x+4)+x

Simplify the arithmetic:

11x+2=(-x+4)+x

Group like terms:

11x+2=(-x+x)+4

Simplify the arithmetic:

11x+2=4

Subtract from both sides:

(11x+2)-2=4-2

Simplify the arithmetic:

11x=42

Simplify the arithmetic:

11x=2

Divide both sides by :

(11x)11=211

Simplify the fraction:

x=211

3. List the solutions

x=-23,211
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|10x+2|
y=|x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.