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Solution - Absolute value equations

Exact form: x=67,143
x=\frac{6}{7} , \frac{14}{3}
Mixed number form: x=67,423
x=\frac{6}{7} , 4\frac{2}{3}
Decimal form: x=0.857,4.667
x=0.857 , 4.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+10|=|2x+4|
without the absolute value bars:

|x|=|y||5x+10|=|2x+4|
x=+y(5x+10)=(2x+4)
x=y(5x+10)=(2x+4)
+x=y(5x+10)=(2x+4)
x=y(5x+10)=(2x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+10|=|2x+4|
x=+y , +x=y(5x+10)=(2x+4)
x=y , x=y(5x+10)=(2x+4)

2. Solve the two equations for x

11 additional steps

(-5x+10)=(2x+4)

Subtract from both sides:

(-5x+10)-2x=(2x+4)-2x

Group like terms:

(-5x-2x)+10=(2x+4)-2x

Simplify the arithmetic:

-7x+10=(2x+4)-2x

Group like terms:

-7x+10=(2x-2x)+4

Simplify the arithmetic:

7x+10=4

Subtract from both sides:

(-7x+10)-10=4-10

Simplify the arithmetic:

7x=410

Simplify the arithmetic:

7x=6

Divide both sides by :

(-7x)-7=-6-7

Cancel out the negatives:

7x7=-6-7

Simplify the fraction:

x=-6-7

Cancel out the negatives:

x=67

12 additional steps

(-5x+10)=-(2x+4)

Expand the parentheses:

(-5x+10)=-2x-4

Add to both sides:

(-5x+10)+2x=(-2x-4)+2x

Group like terms:

(-5x+2x)+10=(-2x-4)+2x

Simplify the arithmetic:

-3x+10=(-2x-4)+2x

Group like terms:

-3x+10=(-2x+2x)-4

Simplify the arithmetic:

3x+10=4

Subtract from both sides:

(-3x+10)-10=-4-10

Simplify the arithmetic:

3x=410

Simplify the arithmetic:

3x=14

Divide both sides by :

(-3x)-3=-14-3

Cancel out the negatives:

3x3=-14-3

Simplify the fraction:

x=-14-3

Cancel out the negatives:

x=143

3. List the solutions

x=67,143
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+10|
y=|2x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.