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Solution - Absolute value equations

Exact form: x=0.02,2.5
x=-0.02 , -2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+1.2|=|3x+1.3|
without the absolute value bars:

|x|=|y||2x+1.2|=|3x+1.3|
x=+y(2x+1.2)=(3x+1.3)
x=y(2x+1.2)=(3x+1.3)
+x=y(2x+1.2)=(3x+1.3)
x=y(2x+1.2)=(3x+1.3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+1.2|=|3x+1.3|
x=+y , +x=y(2x+1.2)=(3x+1.3)
x=y , x=y(2x+1.2)=(3x+1.3)

2. Solve the two equations for x

12 additional steps

(-2x+1.2)=(3x+1.3)

Subtract from both sides:

(-2x+1.2)-3x=(3x+1.3)-3x

Group like terms:

(-2x-3x)+1.2=(3x+1.3)-3x

Simplify the arithmetic:

-5x+1.2=(3x+1.3)-3x

Group like terms:

-5x+1.2=(3x-3x)+1.3

Simplify the arithmetic:

5x+1.2=1.3

Subtract from both sides:

(-5x+1.2)-1.2=1.3-1.2

Simplify the arithmetic:

5x=1.31.2

Simplify the arithmetic:

5x=0.1

Divide both sides by :

(-5x)-5=0.1-5

Cancel out the negatives:

5x5=0.1-5

Simplify the fraction:

x=0.1-5

Move the negative sign from the denominator to the numerator:

x=-0.15

Simplify the arithmetic:

x=0.02

8 additional steps

(-2x+1.2)=-(3x+1.3)

Expand the parentheses:

(-2x+1.2)=-3x-1.3

Add to both sides:

(-2x+1.2)+3x=(-3x-1.3)+3x

Group like terms:

(-2x+3x)+1.2=(-3x-1.3)+3x

Simplify the arithmetic:

x+1.2=(-3x-1.3)+3x

Group like terms:

x+1.2=(-3x+3x)-1.3

Simplify the arithmetic:

x+1.2=1.3

Subtract from both sides:

(x+1.2)-1.2=-1.3-1.2

Simplify the arithmetic:

x=1.31.2

Simplify the arithmetic:

x=2.5

3. List the solutions

x=0.02,2.5
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+1.2|
y=|3x+1.3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.