Enter an equation or problem

Camera input is not recognized!

Solution - Absolute value equations

Exact form:

x = \frac{3}{2}

x=\frac{3}{2}

Mixed number form:

x = 1 \frac{1}{2}

x=1\frac{1}{2}

Decimal form:

x = 1.5

x=1.5

See steps

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

$| - x + 1 | + | - x + 2 | = 0$

Add $- | - x + 2 |$ to both sides of the equation:

$| - x + 1 | + | - x + 2 | - | - x + 2 | = - | - x + 2 |$

Simplify the arithmetic

$| - x + 1 | = - | - x + 2 |$

2. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| - x + 1 | = - | - x + 2 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| - x + 1 \| = - \| - x + 2 \|$
$x = + y$	$(- x + 1) = - (- x + 2)$
$x = - y$	$(- x + 1) = - - (- x + 2)$
$+ x = y$	$(- x + 1) = - (- x + 2)$
$- x = y$	$- (- x + 1) = - (- x + 2)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| - x + 1 \| = - \| - x + 2 \|$
$x = + y$ , $+ x = y$	$(- x + 1) = - (- x + 2)$
$x = - y$ , $- x = y$	$(- x + 1) = - - (- x + 2)$

3. Solve the two equations for x

12 additional steps

$(- x + 1) = - (- x + 2)$

Expand the parentheses:

$(- x + 1) = x - 2$

Subtract from both sides:

$(- x + 1) - x = (x - 2) - x$

Group like terms:

$(- x - x) + 1 = (x - 2) - x$

Simplify the arithmetic:

$- 2 x + 1 = (x - 2) - x$

Group like terms:

$- 2 x + 1 = (x - x) - 2$

Simplify the arithmetic:

$- 2 x + 1 = - 2$

Subtract from both sides:

$(- 2 x + 1) - 1 = - 2 - 1$

Simplify the arithmetic:

$- 2 x = - 2 - 1$

Simplify the arithmetic:

$- 2 x = - 3$

Divide both sides by :

$\frac{(- 2 x)}{- 2} = \frac{- 3}{- 2}$

Cancel out the negatives:

$\frac{2 x}{2} = \frac{- 3}{- 2}$

Simplify the fraction:

$x = \frac{- 3}{- 2}$

Cancel out the negatives:

$x = \frac{3}{2}$

6 additional steps

$(- x + 1) = - (- (- x + 2))$

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

$(- x + 1) = - x + 2$

Add to both sides:

$(- x + 1) + x = (- x + 2) + x$

Group like terms:

$(- x + x) + 1 = (- x + 2) + x$

Simplify the arithmetic:

$1 = (- x + 2) + x$

Group like terms:

$1 = (- x + x) + 2$

Simplify the arithmetic:

$1 = 2$

The statement is false:

$1 = 2$

The equation is false so it has no solution.

4. List the solutions

$x = \frac{3}{2}$
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
$y = | - x + 1 |$
$y = - | - x + 2 |$
The equation is true where the two lines cross.

How did we do?

Please leave us feedback.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for x

4. List the solutions

5. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for x

4. List the solutions

5. Graph

Why learn this

Terms and topics

Related links

Latest Related Drills Solved