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Solution - Absolute value equations

Exact form: l=2
l=2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|l+1|=|l+3|
without the absolute value bars:

|x|=|y||l+1|=|l+3|
x=+y(l+1)=(l+3)
x=y(l+1)=(l+3)
+x=y(l+1)=(l+3)
x=y(l+1)=(l+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||l+1|=|l+3|
x=+y , +x=y(l+1)=(l+3)
x=y , x=y(l+1)=(l+3)

2. Solve the two equations for l

5 additional steps

(-l+1)=(-l+3)

Add to both sides:

(-l+1)+l=(-l+3)+l

Group like terms:

(-l+l)+1=(-l+3)+l

Simplify the arithmetic:

1=(-l+3)+l

Group like terms:

1=(-l+l)+3

Simplify the arithmetic:

1=3

The statement is false:

1=3

The equation is false so it has no solution.

14 additional steps

(-l+1)=-(-l+3)

Expand the parentheses:

(-l+1)=l-3

Subtract from both sides:

(-l+1)-l=(l-3)-l

Group like terms:

(-l-l)+1=(l-3)-l

Simplify the arithmetic:

-2l+1=(l-3)-l

Group like terms:

-2l+1=(l-l)-3

Simplify the arithmetic:

-2l+1=-3

Subtract from both sides:

(-2l+1)-1=-3-1

Simplify the arithmetic:

-2l=-3-1

Simplify the arithmetic:

-2l=-4

Divide both sides by :

(-2l)-2=-4-2

Cancel out the negatives:

2l2=-4-2

Simplify the fraction:

l=-4-2

Cancel out the negatives:

l=42

Find the greatest common factor of the numerator and denominator:

l=(2·2)(1·2)

Factor out and cancel the greatest common factor:

l=2

3. Graph

Each line represents the function of one side of the equation:
y=|l+1|
y=|l+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.