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Solution - Absolute value equations

Exact form: x=-14,12
x=-\frac{1}{4} , \frac{1}{2}
Decimal form: x=0.25,0.5
x=-0.25 , 0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+1|=|x+2|
without the absolute value bars:

|x|=|y||5x+1|=|x+2|
x=+y(5x+1)=(x+2)
x=y(5x+1)=(x+2)
+x=y(5x+1)=(x+2)
x=y(5x+1)=(x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+1|=|x+2|
x=+y , +x=y(5x+1)=(x+2)
x=y , x=y(5x+1)=(x+2)

2. Solve the two equations for x

11 additional steps

(-5x+1)=(-x+2)

Add to both sides:

(-5x+1)+x=(-x+2)+x

Group like terms:

(-5x+x)+1=(-x+2)+x

Simplify the arithmetic:

-4x+1=(-x+2)+x

Group like terms:

-4x+1=(-x+x)+2

Simplify the arithmetic:

4x+1=2

Subtract from both sides:

(-4x+1)-1=2-1

Simplify the arithmetic:

4x=21

Simplify the arithmetic:

4x=1

Divide both sides by :

(-4x)-4=1-4

Cancel out the negatives:

4x4=1-4

Simplify the fraction:

x=1-4

Move the negative sign from the denominator to the numerator:

x=-14

14 additional steps

(-5x+1)=-(-x+2)

Expand the parentheses:

(-5x+1)=x-2

Subtract from both sides:

(-5x+1)-x=(x-2)-x

Group like terms:

(-5x-x)+1=(x-2)-x

Simplify the arithmetic:

-6x+1=(x-2)-x

Group like terms:

-6x+1=(x-x)-2

Simplify the arithmetic:

6x+1=2

Subtract from both sides:

(-6x+1)-1=-2-1

Simplify the arithmetic:

6x=21

Simplify the arithmetic:

6x=3

Divide both sides by :

(-6x)-6=-3-6

Cancel out the negatives:

6x6=-3-6

Simplify the fraction:

x=-3-6

Cancel out the negatives:

x=36

Find the greatest common factor of the numerator and denominator:

x=(1·3)(2·3)

Factor out and cancel the greatest common factor:

x=12

3. List the solutions

x=-14,12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+1|
y=|x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.