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Solution - Absolute value equations

Exact form: x=14,12
x=\frac{1}{4} , \frac{1}{2}
Decimal form: x=0.25,0.5
x=0.25 , 0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+1|=|x|
without the absolute value bars:

|x|=|y||3x+1|=|x|
x=+y(3x+1)=(x)
x=y(3x+1)=(x)
+x=y(3x+1)=(x)
x=y(3x+1)=(x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+1|=|x|
x=+y , +x=y(3x+1)=(x)
x=y , x=y(3x+1)=(x)

2. Solve the two equations for x

10 additional steps

(-3x+1)=x

Subtract from both sides:

(-3x+1)-x=x-x

Group like terms:

(-3x-x)+1=x-x

Simplify the arithmetic:

4x+1=xx

Simplify the arithmetic:

4x+1=0

Subtract from both sides:

(-4x+1)-1=0-1

Simplify the arithmetic:

4x=01

Simplify the arithmetic:

4x=1

Divide both sides by :

(-4x)-4=-1-4

Cancel out the negatives:

4x4=-1-4

Simplify the fraction:

x=-1-4

Cancel out the negatives:

x=14

10 additional steps

(-3x+1)=-x

Add to both sides:

(-3x+1)+x=-x+x

Group like terms:

(-3x+x)+1=-x+x

Simplify the arithmetic:

2x+1=x+x

Simplify the arithmetic:

2x+1=0

Subtract from both sides:

(-2x+1)-1=0-1

Simplify the arithmetic:

2x=01

Simplify the arithmetic:

2x=1

Divide both sides by :

(-2x)-2=-1-2

Cancel out the negatives:

2x2=-1-2

Simplify the fraction:

x=-1-2

Cancel out the negatives:

x=12

3. List the solutions

x=14,12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+1|
y=|x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.