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Solution - Absolute value equations

Exact form: m=1,13
m=1 , \frac{1}{3}
Decimal form: m=1,0.333
m=1 , 0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3m+1|+|3m1|=0

Add |3m1| to both sides of the equation:

|3m+1|+|3m1||3m1|=|3m1|

Simplify the arithmetic

|3m+1|=|3m1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3m+1|=|3m1|
without the absolute value bars:

|x|=|y||3m+1|=|3m1|
x=+y(3m+1)=(3m1)
x=y(3m+1)=(3m1)
+x=y(3m+1)=(3m1)
x=y(3m+1)=(3m1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3m+1|=|3m1|
x=+y , +x=y(3m+1)=(3m1)
x=y , x=y(3m+1)=(3m1)

3. Solve the two equations for m

5 additional steps

(-3m+1)=-(3m-1)

Expand the parentheses:

(-3m+1)=-3m+1

Add to both sides:

(-3m+1)+3m=(-3m+1)+3m

Group like terms:

(-3m+3m)+1=(-3m+1)+3m

Simplify the arithmetic:

1=(-3m+1)+3m

Group like terms:

1=(-3m+3m)+1

Simplify the arithmetic:

1=1

14 additional steps

(-3m+1)=-(-(3m-1))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(-3m+1)=3m-1

Subtract from both sides:

(-3m+1)-3m=(3m-1)-3m

Group like terms:

(-3m-3m)+1=(3m-1)-3m

Simplify the arithmetic:

-6m+1=(3m-1)-3m

Group like terms:

-6m+1=(3m-3m)-1

Simplify the arithmetic:

-6m+1=-1

Subtract from both sides:

(-6m+1)-1=-1-1

Simplify the arithmetic:

-6m=-1-1

Simplify the arithmetic:

-6m=-2

Divide both sides by :

(-6m)-6=-2-6

Cancel out the negatives:

6m6=-2-6

Simplify the fraction:

m=-2-6

Cancel out the negatives:

m=26

Find the greatest common factor of the numerator and denominator:

m=(1·2)(3·2)

Factor out and cancel the greatest common factor:

m=13

4. List the solutions

m=1,13
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3m+1|
y=|3m1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.