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Solution - Absolute value equations

Exact form: i=-122,128
i=-\frac{1}{22} , \frac{1}{28}
Decimal form: i=0.045,0.036
i=-0.045 , 0.036

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3i+1|+|25i|=0

Add |25i| to both sides of the equation:

|3i+1|+|25i||25i|=|25i|

Simplify the arithmetic

|3i+1|=|25i|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3i+1|=|25i|
without the absolute value bars:

|x|=|y||3i+1|=|25i|
x=+y(3i+1)=(25i)
x=y(3i+1)=(25i)
+x=y(3i+1)=(25i)
x=y(3i+1)=(25i)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3i+1|=|25i|
x=+y , +x=y(3i+1)=(25i)
x=y , x=y(3i+1)=(25i)

3. Solve the two equations for i

7 additional steps

(-3i+1)=-25i

Subtract from both sides:

(-3i+1)-1=(-25i)-1

Simplify the arithmetic:

-3i=(-25i)-1

Add to both sides:

(-3i)+25i=((-25i)-1)+25i

Simplify the arithmetic:

22i=((-25i)-1)+25i

Group like terms:

22i=(-25i+25i)-1

Simplify the arithmetic:

22i=1

Divide both sides by :

(22i)22=-122

Simplify the fraction:

i=-122

12 additional steps

(-3i+1)=--25i

Group like terms:

(-3i+1)=(-1·-25)i

Multiply the coefficients:

(-3i+1)=25i

Subtract from both sides:

(-3i+1)-25i=(25i)-25i

Group like terms:

(-3i-25i)+1=(25i)-25i

Simplify the arithmetic:

-28i+1=(25i)-25i

Simplify the arithmetic:

28i+1=0

Subtract from both sides:

(-28i+1)-1=0-1

Simplify the arithmetic:

28i=01

Simplify the arithmetic:

28i=1

Divide both sides by :

(-28i)-28=-1-28

Cancel out the negatives:

28i28=-1-28

Simplify the fraction:

i=-1-28

Cancel out the negatives:

i=128

4. List the solutions

i=-122,128
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3i+1|
y=|25i|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.