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Solution - Absolute value equations

Exact form: i=-32,-18
i=-\frac{3}{2} , -\frac{1}{8}
Mixed number form: i=-112,-18
i=-1\frac{1}{2} , -\frac{1}{8}
Decimal form: i=1.5,0.125
i=-1.5 , -0.125

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3i+1|+|5i+2|=0

Add |5i+2| to both sides of the equation:

|3i+1|+|5i+2||5i+2|=|5i+2|

Simplify the arithmetic

|3i+1|=|5i+2|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3i+1|=|5i+2|
without the absolute value bars:

|x|=|y||3i+1|=|5i+2|
x=+y(3i+1)=(5i+2)
x=y(3i+1)=(5i+2)
+x=y(3i+1)=(5i+2)
x=y(3i+1)=(5i+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3i+1|=|5i+2|
x=+y , +x=y(3i+1)=(5i+2)
x=y , x=y(3i+1)=(5i+2)

3. Solve the two equations for i

10 additional steps

(-3i+1)=-(5i+2)

Expand the parentheses:

(-3i+1)=-5i-2

Add to both sides:

(-3i+1)+5i=(-5i-2)+5i

Group like terms:

(-3i+5i)+1=(-5i-2)+5i

Simplify the arithmetic:

2i+1=(-5i-2)+5i

Group like terms:

2i+1=(-5i+5i)-2

Simplify the arithmetic:

2i+1=2

Subtract from both sides:

(2i+1)-1=-2-1

Simplify the arithmetic:

2i=21

Simplify the arithmetic:

2i=3

Divide both sides by :

(2i)2=-32

Simplify the fraction:

i=-32

12 additional steps

(-3i+1)=-(-(5i+2))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(-3i+1)=5i+2

Subtract from both sides:

(-3i+1)-5i=(5i+2)-5i

Group like terms:

(-3i-5i)+1=(5i+2)-5i

Simplify the arithmetic:

-8i+1=(5i+2)-5i

Group like terms:

-8i+1=(5i-5i)+2

Simplify the arithmetic:

8i+1=2

Subtract from both sides:

(-8i+1)-1=2-1

Simplify the arithmetic:

8i=21

Simplify the arithmetic:

8i=1

Divide both sides by :

(-8i)-8=1-8

Cancel out the negatives:

8i8=1-8

Simplify the fraction:

i=1-8

Move the negative sign from the denominator to the numerator:

i=-18

4. List the solutions

i=-32,-18
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3i+1|
y=|5i+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.