Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=87,2
x=\frac{8}{7} , 2
Mixed number form: x=117,2
x=1\frac{1}{7} , 2
Decimal form: x=1.143,2
x=1.143 , 2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+1|=|5x7|
without the absolute value bars:

|x|=|y||2x+1|=|5x7|
x=+y(2x+1)=(5x7)
x=y(2x+1)=(5x7)
+x=y(2x+1)=(5x7)
x=y(2x+1)=(5x7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+1|=|5x7|
x=+y , +x=y(2x+1)=(5x7)
x=y , x=y(2x+1)=(5x7)

2. Solve the two equations for x

11 additional steps

(-2x+1)=(5x-7)

Subtract from both sides:

(-2x+1)-5x=(5x-7)-5x

Group like terms:

(-2x-5x)+1=(5x-7)-5x

Simplify the arithmetic:

-7x+1=(5x-7)-5x

Group like terms:

-7x+1=(5x-5x)-7

Simplify the arithmetic:

7x+1=7

Subtract from both sides:

(-7x+1)-1=-7-1

Simplify the arithmetic:

7x=71

Simplify the arithmetic:

7x=8

Divide both sides by :

(-7x)-7=-8-7

Cancel out the negatives:

7x7=-8-7

Simplify the fraction:

x=-8-7

Cancel out the negatives:

x=87

12 additional steps

(-2x+1)=-(5x-7)

Expand the parentheses:

(-2x+1)=-5x+7

Add to both sides:

(-2x+1)+5x=(-5x+7)+5x

Group like terms:

(-2x+5x)+1=(-5x+7)+5x

Simplify the arithmetic:

3x+1=(-5x+7)+5x

Group like terms:

3x+1=(-5x+5x)+7

Simplify the arithmetic:

3x+1=7

Subtract from both sides:

(3x+1)-1=7-1

Simplify the arithmetic:

3x=71

Simplify the arithmetic:

3x=6

Divide both sides by :

(3x)3=63

Simplify the fraction:

x=63

Find the greatest common factor of the numerator and denominator:

x=(2·3)(1·3)

Factor out and cancel the greatest common factor:

x=2

3. List the solutions

x=87,2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+1|
y=|5x7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.