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Solution - Absolute value equations

Exact form: y=0.152,0.106
y=-0.152 , 0.106

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|0.07y0.05|=|0.4y|
without the absolute value bars:

|x|=|y||0.07y0.05|=|0.4y|
x=+y(0.07y0.05)=(0.4y)
x=y(0.07y0.05)=(0.4y)
+x=y(0.07y0.05)=(0.4y)
x=y(0.07y0.05)=(0.4y)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||0.07y0.05|=|0.4y|
x=+y , +x=y(0.07y0.05)=(0.4y)
x=y , x=y(0.07y0.05)=(0.4y)

2. Solve the two equations for y

11 additional steps

(0.07y-0.05)=0.4y

Subtract from both sides:

(0.07y-0.05)-0.4y=(0.4y)-0.4y

Group like terms:

(0.07y-0.4y)-0.05=(0.4y)-0.4y

Simplify the arithmetic:

-0.33y-0.05=(0.4y)-0.4y

Simplify the arithmetic:

0.33y0.05=0

Add to both sides:

(-0.33y-0.05)+0.05=0+0.05

Simplify the arithmetic:

0.33y=0+0.05

Simplify the arithmetic:

0.33y=0.05

Divide both sides by :

(-0.33y)-0.33=0.05-0.33

Cancel out the negatives:

0.33y0.33=0.05-0.33

Simplify the arithmetic:

y=0.05-0.33

Move the negative sign from the denominator to the numerator:

y=-0.050.33

Simplify the arithmetic:

y=0.1515

8 additional steps

(0.07y-0.05)=-0.4y

Add to both sides:

(0.07y-0.05)+0.05=(-0.4y)+0.05

Simplify the arithmetic:

0.07y=(-0.4y)+0.05

Add to both sides:

(0.07y)+0.4y=((-0.4y)+0.05)+0.4y

Simplify the arithmetic:

0.47y=((-0.4y)+0.05)+0.4y

Group like terms:

0.47y=(-0.4y+0.4y)+0.05

Simplify the arithmetic:

0.47y=0.05

Divide both sides by :

(0.47y)0.47=0.050.47

Simplify the arithmetic:

y=0.050.47

Simplify the arithmetic:

y=0.1064

3. List the solutions

y=0.152,0.106
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|0.07y0.05|
y=|0.4y|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.