Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: y=-12,54
y=-\frac{1}{2} , \frac{5}{4}
Mixed number form: y=-12,114
y=-\frac{1}{2} , 1\frac{1}{4}
Decimal form: y=0.5,1.25
y=-0.5 , 1.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|y+3|=|3y+2|
without the absolute value bars:

|x|=|y||y+3|=|3y+2|
x=+y(y+3)=(3y+2)
x=y(y+3)=(3y+2)
+x=y(y+3)=(3y+2)
x=y(y+3)=(3y+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||y+3|=|3y+2|
x=+y , +x=y(y+3)=(3y+2)
x=y , x=y(y+3)=(3y+2)

2. Solve the two equations for y

9 additional steps

(-y+3)=(-3y+2)

Add to both sides:

(-y+3)+3y=(-3y+2)+3y

Group like terms:

(-y+3y)+3=(-3y+2)+3y

Simplify the arithmetic:

2y+3=(-3y+2)+3y

Group like terms:

2y+3=(-3y+3y)+2

Simplify the arithmetic:

2y+3=2

Subtract from both sides:

(2y+3)-3=2-3

Simplify the arithmetic:

2y=23

Simplify the arithmetic:

2y=1

Divide both sides by :

(2y)2=-12

Simplify the fraction:

y=-12

12 additional steps

(-y+3)=-(-3y+2)

Expand the parentheses:

(-y+3)=3y-2

Subtract from both sides:

(-y+3)-3y=(3y-2)-3y

Group like terms:

(-y-3y)+3=(3y-2)-3y

Simplify the arithmetic:

-4y+3=(3y-2)-3y

Group like terms:

-4y+3=(3y-3y)-2

Simplify the arithmetic:

4y+3=2

Subtract from both sides:

(-4y+3)-3=-2-3

Simplify the arithmetic:

4y=23

Simplify the arithmetic:

4y=5

Divide both sides by :

(-4y)-4=-5-4

Cancel out the negatives:

4y4=-5-4

Simplify the fraction:

y=-5-4

Cancel out the negatives:

y=54

3. List the solutions

y=-12,54
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|y+3|
y=|3y+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.