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Solution - Absolute value equations

Exact form: x=-87,85
x=-\frac{8}{7} , \frac{8}{5}
Mixed number form: x=-117,135
x=-1\frac{1}{7} , 1\frac{3}{5}
Decimal form: x=1.143,1.6
x=-1.143 , 1.6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x8|=2|3x|
without the absolute value bars:

|x|=|y||x8|=2|3x|
x=+y(x8)=2(3x)
x=y(x8)=2((3x))
+x=y(x8)=2(3x)
x=y(x8)=2(3x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x8|=2|3x|
x=+y , +x=y(x8)=2(3x)
x=y , x=y(x8)=2((3x))

2. Solve the two equations for x

11 additional steps

(-x-8)=2·3x

Multiply the coefficients:

(-x-8)=6x

Subtract from both sides:

(-x-8)-6x=(6x)-6x

Group like terms:

(-x-6x)-8=(6x)-6x

Simplify the arithmetic:

-7x-8=(6x)-6x

Simplify the arithmetic:

7x8=0

Add to both sides:

(-7x-8)+8=0+8

Simplify the arithmetic:

7x=0+8

Simplify the arithmetic:

7x=8

Divide both sides by :

(-7x)-7=8-7

Cancel out the negatives:

7x7=8-7

Simplify the fraction:

x=8-7

Move the negative sign from the denominator to the numerator:

x=-87

9 additional steps

(-x-8)=2·-3x

Multiply the coefficients:

(-x-8)=-6x

Add to both sides:

(-x-8)+6x=(-6x)+6x

Group like terms:

(-x+6x)-8=(-6x)+6x

Simplify the arithmetic:

5x-8=(-6x)+6x

Simplify the arithmetic:

5x8=0

Add to both sides:

(5x-8)+8=0+8

Simplify the arithmetic:

5x=0+8

Simplify the arithmetic:

5x=8

Divide both sides by :

(5x)5=85

Simplify the fraction:

x=85

3. List the solutions

x=-87,85
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x8|
y=2|3x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.