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Solution - Absolute value equations

Exact form: w=-74
w=-\frac{7}{4}
Mixed number form: w=-134
w=-1\frac{3}{4}
Decimal form: w=1.75
w=-1.75

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4w9|=|4w+5|
without the absolute value bars:

|x|=|y||4w9|=|4w+5|
x=+y(4w9)=(4w+5)
x=y(4w9)=(4w+5)
+x=y(4w9)=(4w+5)
x=y(4w9)=(4w+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4w9|=|4w+5|
x=+y , +x=y(4w9)=(4w+5)
x=y , x=y(4w9)=(4w+5)

2. Solve the two equations for w

13 additional steps

(-4w-9)=(4w+5)

Subtract from both sides:

(-4w-9)-4w=(4w+5)-4w

Group like terms:

(-4w-4w)-9=(4w+5)-4w

Simplify the arithmetic:

-8w-9=(4w+5)-4w

Group like terms:

-8w-9=(4w-4w)+5

Simplify the arithmetic:

8w9=5

Add to both sides:

(-8w-9)+9=5+9

Simplify the arithmetic:

8w=5+9

Simplify the arithmetic:

8w=14

Divide both sides by :

(-8w)-8=14-8

Cancel out the negatives:

8w8=14-8

Simplify the fraction:

w=14-8

Move the negative sign from the denominator to the numerator:

w=-148

Find the greatest common factor of the numerator and denominator:

w=(-7·2)(4·2)

Factor out and cancel the greatest common factor:

w=-74

6 additional steps

(-4w-9)=-(4w+5)

Expand the parentheses:

(-4w-9)=-4w-5

Add to both sides:

(-4w-9)+4w=(-4w-5)+4w

Group like terms:

(-4w+4w)-9=(-4w-5)+4w

Simplify the arithmetic:

-9=(-4w-5)+4w

Group like terms:

-9=(-4w+4w)-5

Simplify the arithmetic:

9=5

The statement is false:

9=5

The equation is false so it has no solution.

3. List the solutions

w=-74
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4w9|
y=|4w+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.