Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=118,-92
x=\frac{1}{18} , -\frac{9}{2}
Mixed number form: x=118,-412
x=\frac{1}{18} , -4\frac{1}{2}
Decimal form: x=0.056,4.5
x=0.056 , -4.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x+5|=|10x+4|
without the absolute value bars:

|x|=|y||8x+5|=|10x+4|
x=+y(8x+5)=(10x+4)
x=y(8x+5)=(10x+4)
+x=y(8x+5)=(10x+4)
x=y(8x+5)=(10x+4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x+5|=|10x+4|
x=+y , +x=y(8x+5)=(10x+4)
x=y , x=y(8x+5)=(10x+4)

2. Solve the two equations for x

11 additional steps

(-8x+5)=(10x+4)

Subtract from both sides:

(-8x+5)-10x=(10x+4)-10x

Group like terms:

(-8x-10x)+5=(10x+4)-10x

Simplify the arithmetic:

-18x+5=(10x+4)-10x

Group like terms:

-18x+5=(10x-10x)+4

Simplify the arithmetic:

18x+5=4

Subtract from both sides:

(-18x+5)-5=4-5

Simplify the arithmetic:

18x=45

Simplify the arithmetic:

18x=1

Divide both sides by :

(-18x)-18=-1-18

Cancel out the negatives:

18x18=-1-18

Simplify the fraction:

x=-1-18

Cancel out the negatives:

x=118

10 additional steps

(-8x+5)=-(10x+4)

Expand the parentheses:

(-8x+5)=-10x-4

Add to both sides:

(-8x+5)+10x=(-10x-4)+10x

Group like terms:

(-8x+10x)+5=(-10x-4)+10x

Simplify the arithmetic:

2x+5=(-10x-4)+10x

Group like terms:

2x+5=(-10x+10x)-4

Simplify the arithmetic:

2x+5=4

Subtract from both sides:

(2x+5)-5=-4-5

Simplify the arithmetic:

2x=45

Simplify the arithmetic:

2x=9

Divide both sides by :

(2x)2=-92

Simplify the fraction:

x=-92

3. List the solutions

x=118,-92
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x+5|
y=|10x+4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.