Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=1011,-25
x=\frac{10}{11} , -\frac{2}{5}
Decimal form: x=0.909,0.4
x=0.909 , -0.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|8x+4|=|3x6|
without the absolute value bars:

|x|=|y||8x+4|=|3x6|
x=+y(8x+4)=(3x6)
x=y(8x+4)=(3x6)
+x=y(8x+4)=(3x6)
x=y(8x+4)=(3x6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||8x+4|=|3x6|
x=+y , +x=y(8x+4)=(3x6)
x=y , x=y(8x+4)=(3x6)

2. Solve the two equations for x

11 additional steps

(-8x+4)=(3x-6)

Subtract from both sides:

(-8x+4)-3x=(3x-6)-3x

Group like terms:

(-8x-3x)+4=(3x-6)-3x

Simplify the arithmetic:

-11x+4=(3x-6)-3x

Group like terms:

-11x+4=(3x-3x)-6

Simplify the arithmetic:

11x+4=6

Subtract from both sides:

(-11x+4)-4=-6-4

Simplify the arithmetic:

11x=64

Simplify the arithmetic:

11x=10

Divide both sides by :

(-11x)-11=-10-11

Cancel out the negatives:

11x11=-10-11

Simplify the fraction:

x=-10-11

Cancel out the negatives:

x=1011

12 additional steps

(-8x+4)=-(3x-6)

Expand the parentheses:

(-8x+4)=-3x+6

Add to both sides:

(-8x+4)+3x=(-3x+6)+3x

Group like terms:

(-8x+3x)+4=(-3x+6)+3x

Simplify the arithmetic:

-5x+4=(-3x+6)+3x

Group like terms:

-5x+4=(-3x+3x)+6

Simplify the arithmetic:

5x+4=6

Subtract from both sides:

(-5x+4)-4=6-4

Simplify the arithmetic:

5x=64

Simplify the arithmetic:

5x=2

Divide both sides by :

(-5x)-5=2-5

Cancel out the negatives:

5x5=2-5

Simplify the fraction:

x=2-5

Move the negative sign from the denominator to the numerator:

x=-25

3. List the solutions

x=1011,-25
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|8x+4|
y=|3x6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.