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Solution - Absolute value equations

Exact form: x=-115,3
x=-\frac{1}{15} , 3
Decimal form: x=0.067,3
x=-0.067 , 3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|6x5|=|9x4|
without the absolute value bars:

|x|=|y||6x5|=|9x4|
x=+y(6x5)=(9x4)
x=y(6x5)=(9x4)
+x=y(6x5)=(9x4)
x=y(6x5)=(9x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||6x5|=|9x4|
x=+y , +x=y(6x5)=(9x4)
x=y , x=y(6x5)=(9x4)

2. Solve the two equations for x

11 additional steps

(-6x-5)=(9x-4)

Subtract from both sides:

(-6x-5)-9x=(9x-4)-9x

Group like terms:

(-6x-9x)-5=(9x-4)-9x

Simplify the arithmetic:

-15x-5=(9x-4)-9x

Group like terms:

-15x-5=(9x-9x)-4

Simplify the arithmetic:

15x5=4

Add to both sides:

(-15x-5)+5=-4+5

Simplify the arithmetic:

15x=4+5

Simplify the arithmetic:

15x=1

Divide both sides by :

(-15x)-15=1-15

Cancel out the negatives:

15x15=1-15

Simplify the fraction:

x=1-15

Move the negative sign from the denominator to the numerator:

x=-115

12 additional steps

(-6x-5)=-(9x-4)

Expand the parentheses:

(-6x-5)=-9x+4

Add to both sides:

(-6x-5)+9x=(-9x+4)+9x

Group like terms:

(-6x+9x)-5=(-9x+4)+9x

Simplify the arithmetic:

3x-5=(-9x+4)+9x

Group like terms:

3x-5=(-9x+9x)+4

Simplify the arithmetic:

3x5=4

Add to both sides:

(3x-5)+5=4+5

Simplify the arithmetic:

3x=4+5

Simplify the arithmetic:

3x=9

Divide both sides by :

(3x)3=93

Simplify the fraction:

x=93

Find the greatest common factor of the numerator and denominator:

x=(3·3)(1·3)

Factor out and cancel the greatest common factor:

x=3

3. List the solutions

x=-115,3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|6x5|
y=|9x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.