Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=23,-67
x=\frac{2}{3} , -\frac{6}{7}
Decimal form: x=0.667,0.857
x=0.667 , -0.857

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x2|=|2x4|
without the absolute value bars:

|x|=|y||5x2|=|2x4|
x=+y(5x2)=(2x4)
x=y(5x2)=(2x4)
+x=y(5x2)=(2x4)
x=y(5x2)=(2x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x2|=|2x4|
x=+y , +x=y(5x2)=(2x4)
x=y , x=y(5x2)=(2x4)

2. Solve the two equations for x

11 additional steps

(-5x-2)=(-2x-4)

Add to both sides:

(-5x-2)+2x=(-2x-4)+2x

Group like terms:

(-5x+2x)-2=(-2x-4)+2x

Simplify the arithmetic:

-3x-2=(-2x-4)+2x

Group like terms:

-3x-2=(-2x+2x)-4

Simplify the arithmetic:

3x2=4

Add to both sides:

(-3x-2)+2=-4+2

Simplify the arithmetic:

3x=4+2

Simplify the arithmetic:

3x=2

Divide both sides by :

(-3x)-3=-2-3

Cancel out the negatives:

3x3=-2-3

Simplify the fraction:

x=-2-3

Cancel out the negatives:

x=23

12 additional steps

(-5x-2)=-(-2x-4)

Expand the parentheses:

(-5x-2)=2x+4

Subtract from both sides:

(-5x-2)-2x=(2x+4)-2x

Group like terms:

(-5x-2x)-2=(2x+4)-2x

Simplify the arithmetic:

-7x-2=(2x+4)-2x

Group like terms:

-7x-2=(2x-2x)+4

Simplify the arithmetic:

7x2=4

Add to both sides:

(-7x-2)+2=4+2

Simplify the arithmetic:

7x=4+2

Simplify the arithmetic:

7x=6

Divide both sides by :

(-7x)-7=6-7

Cancel out the negatives:

7x7=6-7

Simplify the fraction:

x=6-7

Move the negative sign from the denominator to the numerator:

x=-67

3. List the solutions

x=23,-67
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x2|
y=|2x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.