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Solution - Absolute value equations

Exact form: x=0,29
x=0 , \frac{2}{9}
Decimal form: x=0,0.222
x=0 , 0.222

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|5x+1|+|4x1|=0

Add |4x1| to both sides of the equation:

|5x+1|+|4x1||4x1|=|4x1|

Simplify the arithmetic

|5x+1|=|4x1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+1|=|4x1|
without the absolute value bars:

|x|=|y||5x+1|=|4x1|
x=+y(5x+1)=(4x1)
x=y(5x+1)=(4x1)
+x=y(5x+1)=(4x1)
x=y(5x+1)=(4x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+1|=|4x1|
x=+y , +x=y(5x+1)=(4x1)
x=y , x=y(5x+1)=(4x1)

3. Solve the two equations for x

11 additional steps

(-5x+1)=-(4x-1)

Expand the parentheses:

(-5x+1)=-4x+1

Add to both sides:

(-5x+1)+4x=(-4x+1)+4x

Group like terms:

(-5x+4x)+1=(-4x+1)+4x

Simplify the arithmetic:

-x+1=(-4x+1)+4x

Group like terms:

-x+1=(-4x+4x)+1

Simplify the arithmetic:

x+1=1

Subtract from both sides:

(-x+1)-1=1-1

Simplify the arithmetic:

x=11

Simplify the arithmetic:

x=0

Multiply both sides by :

-x·-1=0·-1

Remove the one(s):

x=0·-1

Multiply by zero:

x=0

12 additional steps

(-5x+1)=-(-(4x-1))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(-5x+1)=4x-1

Subtract from both sides:

(-5x+1)-4x=(4x-1)-4x

Group like terms:

(-5x-4x)+1=(4x-1)-4x

Simplify the arithmetic:

-9x+1=(4x-1)-4x

Group like terms:

-9x+1=(4x-4x)-1

Simplify the arithmetic:

9x+1=1

Subtract from both sides:

(-9x+1)-1=-1-1

Simplify the arithmetic:

9x=11

Simplify the arithmetic:

9x=2

Divide both sides by :

(-9x)-9=-2-9

Cancel out the negatives:

9x9=-2-9

Simplify the fraction:

x=-2-9

Cancel out the negatives:

x=29

4. List the solutions

x=0,29
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|5x+1|
y=|4x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.