Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=49,-2
x=\frac{4}{9} , -2
Decimal form: x=0.444,2
x=0.444 , -2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+1|=|4x3|
without the absolute value bars:

|x|=|y||5x+1|=|4x3|
x=+y(5x+1)=(4x3)
x=y(5x+1)=(4x3)
+x=y(5x+1)=(4x3)
x=y(5x+1)=(4x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+1|=|4x3|
x=+y , +x=y(5x+1)=(4x3)
x=y , x=y(5x+1)=(4x3)

2. Solve the two equations for x

11 additional steps

(-5x+1)=(4x-3)

Subtract from both sides:

(-5x+1)-4x=(4x-3)-4x

Group like terms:

(-5x-4x)+1=(4x-3)-4x

Simplify the arithmetic:

-9x+1=(4x-3)-4x

Group like terms:

-9x+1=(4x-4x)-3

Simplify the arithmetic:

9x+1=3

Subtract from both sides:

(-9x+1)-1=-3-1

Simplify the arithmetic:

9x=31

Simplify the arithmetic:

9x=4

Divide both sides by :

(-9x)-9=-4-9

Cancel out the negatives:

9x9=-4-9

Simplify the fraction:

x=-4-9

Cancel out the negatives:

x=49

11 additional steps

(-5x+1)=-(4x-3)

Expand the parentheses:

(-5x+1)=-4x+3

Add to both sides:

(-5x+1)+4x=(-4x+3)+4x

Group like terms:

(-5x+4x)+1=(-4x+3)+4x

Simplify the arithmetic:

-x+1=(-4x+3)+4x

Group like terms:

-x+1=(-4x+4x)+3

Simplify the arithmetic:

x+1=3

Subtract from both sides:

(-x+1)-1=3-1

Simplify the arithmetic:

x=31

Simplify the arithmetic:

x=2

Multiply both sides by :

-x·-1=2·-1

Remove the one(s):

x=2·-1

Simplify the arithmetic:

x=2

3. List the solutions

x=49,-2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+1|
y=|4x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.