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Solution - Absolute value equations

Exact form: y=-74
y=-\frac{7}{4}
Mixed number form: y=-134
y=-1\frac{3}{4}
Decimal form: y=1.75
y=-1.75

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|4y5|=|4y+9|
without the absolute value bars:

|x|=|y||4y5|=|4y+9|
x=+y(4y5)=(4y+9)
x=y(4y5)=(4y+9)
+x=y(4y5)=(4y+9)
x=y(4y5)=(4y+9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||4y5|=|4y+9|
x=+y , +x=y(4y5)=(4y+9)
x=y , x=y(4y5)=(4y+9)

2. Solve the two equations for y

13 additional steps

(-4y-5)=(4y+9)

Subtract from both sides:

(-4y-5)-4y=(4y+9)-4y

Group like terms:

(-4y-4y)-5=(4y+9)-4y

Simplify the arithmetic:

-8y-5=(4y+9)-4y

Group like terms:

-8y-5=(4y-4y)+9

Simplify the arithmetic:

8y5=9

Add to both sides:

(-8y-5)+5=9+5

Simplify the arithmetic:

8y=9+5

Simplify the arithmetic:

8y=14

Divide both sides by :

(-8y)-8=14-8

Cancel out the negatives:

8y8=14-8

Simplify the fraction:

y=14-8

Move the negative sign from the denominator to the numerator:

y=-148

Find the greatest common factor of the numerator and denominator:

y=(-7·2)(4·2)

Factor out and cancel the greatest common factor:

y=-74

6 additional steps

(-4y-5)=-(4y+9)

Expand the parentheses:

(-4y-5)=-4y-9

Add to both sides:

(-4y-5)+4y=(-4y-9)+4y

Group like terms:

(-4y+4y)-5=(-4y-9)+4y

Simplify the arithmetic:

-5=(-4y-9)+4y

Group like terms:

-5=(-4y+4y)-9

Simplify the arithmetic:

5=9

The statement is false:

5=9

The equation is false so it has no solution.

3. List the solutions

y=-74
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|4y5|
y=|4y+9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.