Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: v=-32
v=-\frac{3}{2}
Mixed number form: v=-112
v=-1\frac{1}{2}
Decimal form: v=1.5
v=-1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3v4|=|3v+5|
without the absolute value bars:

|x|=|y||3v4|=|3v+5|
x=+y(3v4)=(3v+5)
x=y(3v4)=(3v+5)
+x=y(3v4)=(3v+5)
x=y(3v4)=(3v+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3v4|=|3v+5|
x=+y , +x=y(3v4)=(3v+5)
x=y , x=y(3v4)=(3v+5)

2. Solve the two equations for v

13 additional steps

(-3v-4)=(3v+5)

Subtract from both sides:

(-3v-4)-3v=(3v+5)-3v

Group like terms:

(-3v-3v)-4=(3v+5)-3v

Simplify the arithmetic:

-6v-4=(3v+5)-3v

Group like terms:

-6v-4=(3v-3v)+5

Simplify the arithmetic:

6v4=5

Add to both sides:

(-6v-4)+4=5+4

Simplify the arithmetic:

6v=5+4

Simplify the arithmetic:

6v=9

Divide both sides by :

(-6v)-6=9-6

Cancel out the negatives:

6v6=9-6

Simplify the fraction:

v=9-6

Move the negative sign from the denominator to the numerator:

v=-96

Find the greatest common factor of the numerator and denominator:

v=(-3·3)(2·3)

Factor out and cancel the greatest common factor:

v=-32

6 additional steps

(-3v-4)=-(3v+5)

Expand the parentheses:

(-3v-4)=-3v-5

Add to both sides:

(-3v-4)+3v=(-3v-5)+3v

Group like terms:

(-3v+3v)-4=(-3v-5)+3v

Simplify the arithmetic:

-4=(-3v-5)+3v

Group like terms:

-4=(-3v+3v)-5

Simplify the arithmetic:

4=5

The statement is false:

4=5

The equation is false so it has no solution.

3. List the solutions

v=-32
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3v4|
y=|3v+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.