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Solution - Absolute value equations

Exact form: v=12
v=\frac{1}{2}
Decimal form: v=0.5
v=0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2v4|=|2v6|
without the absolute value bars:

|x|=|y||2v4|=|2v6|
x=+y(2v4)=(2v6)
x=y(2v4)=(2v6)
+x=y(2v4)=(2v6)
x=y(2v4)=(2v6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2v4|=|2v6|
x=+y , +x=y(2v4)=(2v6)
x=y , x=y(2v4)=(2v6)

2. Solve the two equations for v

13 additional steps

(-2v-4)=(2v-6)

Subtract from both sides:

(-2v-4)-2v=(2v-6)-2v

Group like terms:

(-2v-2v)-4=(2v-6)-2v

Simplify the arithmetic:

-4v-4=(2v-6)-2v

Group like terms:

-4v-4=(2v-2v)-6

Simplify the arithmetic:

4v4=6

Add to both sides:

(-4v-4)+4=-6+4

Simplify the arithmetic:

4v=6+4

Simplify the arithmetic:

4v=2

Divide both sides by :

(-4v)-4=-2-4

Cancel out the negatives:

4v4=-2-4

Simplify the fraction:

v=-2-4

Cancel out the negatives:

v=24

Find the greatest common factor of the numerator and denominator:

v=(1·2)(2·2)

Factor out and cancel the greatest common factor:

v=12

6 additional steps

(-2v-4)=-(2v-6)

Expand the parentheses:

(-2v-4)=-2v+6

Add to both sides:

(-2v-4)+2v=(-2v+6)+2v

Group like terms:

(-2v+2v)-4=(-2v+6)+2v

Simplify the arithmetic:

-4=(-2v+6)+2v

Group like terms:

-4=(-2v+2v)+6

Simplify the arithmetic:

4=6

The statement is false:

4=6

The equation is false so it has no solution.

3. List the solutions

v=12
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2v4|
y=|2v6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.