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Solution - Absolute value equations

Exact form: x=12,-38
x=\frac{1}{2} , -\frac{3}{8}
Decimal form: x=0.5,0.375
x=0.5 , -0.375

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x2|=|5x1|
without the absolute value bars:

|x|=|y||3x2|=|5x1|
x=+y(3x2)=(5x1)
x=y(3x2)=(5x1)
+x=y(3x2)=(5x1)
x=y(3x2)=(5x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x2|=|5x1|
x=+y , +x=y(3x2)=(5x1)
x=y , x=y(3x2)=(5x1)

2. Solve the two equations for x

9 additional steps

(-3x-2)=(-5x-1)

Add to both sides:

(-3x-2)+5x=(-5x-1)+5x

Group like terms:

(-3x+5x)-2=(-5x-1)+5x

Simplify the arithmetic:

2x-2=(-5x-1)+5x

Group like terms:

2x-2=(-5x+5x)-1

Simplify the arithmetic:

2x2=1

Add to both sides:

(2x-2)+2=-1+2

Simplify the arithmetic:

2x=1+2

Simplify the arithmetic:

2x=1

Divide both sides by :

(2x)2=12

Simplify the fraction:

x=12

12 additional steps

(-3x-2)=-(-5x-1)

Expand the parentheses:

(-3x-2)=5x+1

Subtract from both sides:

(-3x-2)-5x=(5x+1)-5x

Group like terms:

(-3x-5x)-2=(5x+1)-5x

Simplify the arithmetic:

-8x-2=(5x+1)-5x

Group like terms:

-8x-2=(5x-5x)+1

Simplify the arithmetic:

8x2=1

Add to both sides:

(-8x-2)+2=1+2

Simplify the arithmetic:

8x=1+2

Simplify the arithmetic:

8x=3

Divide both sides by :

(-8x)-8=3-8

Cancel out the negatives:

8x8=3-8

Simplify the fraction:

x=3-8

Move the negative sign from the denominator to the numerator:

x=-38

3. List the solutions

x=12,-38
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x2|
y=|5x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.