Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=0,0
x=0 , 0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x|=|7x|
without the absolute value bars:

|x|=|y||3x|=|7x|
x=+y(3x)=(7x)
x=y(3x)=(7x)
+x=y(3x)=(7x)
x=y(3x)=(7x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x|=|7x|
x=+y , +x=y(3x)=(7x)
x=y , x=y(3x)=(7x)

2. Solve the two equations for x

3 additional steps

(-3x)=7x

Subtract from both sides:

(-3x)-7x=(7x)-7x

Simplify the arithmetic:

-10x=(7x)-7x

Simplify the arithmetic:

10x=0

Divide both sides by the coefficient:

x=0

13 additional steps

(-3x)=-7x

Divide both sides by :

(-3x)-3=(-7x)-3

Cancel out the negatives:

3x3=(-7x)-3

Simplify the fraction:

x=(-7x)-3

Cancel out the negatives:

x=7x3

Subtract from both sides:

x-7x3=(7x3)-7x3

Group the coefficients:

(1+-73)x=(7x3)-7x3

Convert the integer into a fraction:

(33+-73)x=(7x3)-7x3

Combine the fractions:

(3-7)3x=(7x3)-7x3

Combine the numerators:

-43x=(7x3)-7x3

Combine the fractions:

-43·x=(7-7)3x

Combine the numerators:

-43·x=03x

Reduce the zero numerator:

-43x=0x

Simplify the arithmetic:

-43x=0

Divide both sides by the coefficient:

x=0

3. List the solutions

x=0,0
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x|
y=|7x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.