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Solution - Absolute value equations

Exact form: x=79,53
x=\frac{7}{9} , \frac{5}{3}
Mixed number form: x=79,123
x=\frac{7}{9} , 1\frac{2}{3}
Decimal form: x=0.778,1.667
x=0.778 , 1.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x+1|=|6x6|
without the absolute value bars:

|x|=|y||3x+1|=|6x6|
x=+y(3x+1)=(6x6)
x=y(3x+1)=(6x6)
+x=y(3x+1)=(6x6)
x=y(3x+1)=(6x6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x+1|=|6x6|
x=+y , +x=y(3x+1)=(6x6)
x=y , x=y(3x+1)=(6x6)

2. Solve the two equations for x

11 additional steps

(-3x+1)=(6x-6)

Subtract from both sides:

(-3x+1)-6x=(6x-6)-6x

Group like terms:

(-3x-6x)+1=(6x-6)-6x

Simplify the arithmetic:

-9x+1=(6x-6)-6x

Group like terms:

-9x+1=(6x-6x)-6

Simplify the arithmetic:

9x+1=6

Subtract from both sides:

(-9x+1)-1=-6-1

Simplify the arithmetic:

9x=61

Simplify the arithmetic:

9x=7

Divide both sides by :

(-9x)-9=-7-9

Cancel out the negatives:

9x9=-7-9

Simplify the fraction:

x=-7-9

Cancel out the negatives:

x=79

10 additional steps

(-3x+1)=-(6x-6)

Expand the parentheses:

(-3x+1)=-6x+6

Add to both sides:

(-3x+1)+6x=(-6x+6)+6x

Group like terms:

(-3x+6x)+1=(-6x+6)+6x

Simplify the arithmetic:

3x+1=(-6x+6)+6x

Group like terms:

3x+1=(-6x+6x)+6

Simplify the arithmetic:

3x+1=6

Subtract from both sides:

(3x+1)-1=6-1

Simplify the arithmetic:

3x=61

Simplify the arithmetic:

3x=5

Divide both sides by :

(3x)3=53

Simplify the fraction:

x=53

3. List the solutions

x=79,53
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x+1|
y=|6x6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.