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Solution - Absolute value equations

Exact form: t=2,6
t=2 , 6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3t+6|=3|t2|
without the absolute value bars:

|x|=|y||3t+6|=3|t2|
x=+y(3t+6)=3(t2)
x=y(3t+6)=3((t2))
+x=y(3t+6)=3(t2)
x=y(3t+6)=3(t2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3t+6|=3|t2|
x=+y , +x=y(3t+6)=3(t2)
x=y , x=y(3t+6)=3((t2))

2. Solve the two equations for t

15 additional steps

(-3t+6)=3·(t-2)

Expand the parentheses:

(-3t+6)=3t+3·-2

Simplify the arithmetic:

(-3t+6)=3t-6

Subtract from both sides:

(-3t+6)-3t=(3t-6)-3t

Group like terms:

(-3t-3t)+6=(3t-6)-3t

Simplify the arithmetic:

-6t+6=(3t-6)-3t

Group like terms:

-6t+6=(3t-3t)-6

Simplify the arithmetic:

6t+6=6

Subtract from both sides:

(-6t+6)-6=-6-6

Simplify the arithmetic:

6t=66

Simplify the arithmetic:

6t=12

Divide both sides by :

(-6t)-6=-12-6

Cancel out the negatives:

6t6=-12-6

Simplify the fraction:

t=-12-6

Cancel out the negatives:

t=126

Find the greatest common factor of the numerator and denominator:

t=(2·6)(1·6)

Factor out and cancel the greatest common factor:

t=2

9 additional steps

(-3t+6)=3·(-(t-2))

Expand the parentheses:

(-3t+6)=3·(-t+2)

(-3t+6)=3·-t+3·2

Group like terms:

(-3t+6)=(3·-1)t+3·2

Multiply the coefficients:

(-3t+6)=-3t+3·2

Simplify the arithmetic:

(-3t+6)=-3t+6

Add to both sides:

(-3t+6)+3t=(-3t+6)+3t

Group like terms:

(-3t+3t)+6=(-3t+6)+3t

Simplify the arithmetic:

6=(-3t+6)+3t

Group like terms:

6=(-3t+3t)+6

Simplify the arithmetic:

6=6

3. List the solutions

t=2,6
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3t+6|
y=3|t2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.