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Solution - Absolute value equations

Exact form: s=10,12
s=10 , \frac{1}{2}
Decimal form: s=10,0.5
s=10 , 0.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3s+11|=|s9|
without the absolute value bars:

|x|=|y||3s+11|=|s9|
x=+y(3s+11)=(s9)
x=y(3s+11)=(s9)
+x=y(3s+11)=(s9)
x=y(3s+11)=(s9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3s+11|=|s9|
x=+y , +x=y(3s+11)=(s9)
x=y , x=y(3s+11)=(s9)

2. Solve the two equations for s

13 additional steps

(-3s+11)=(-s-9)

Add to both sides:

(-3s+11)+s=(-s-9)+s

Group like terms:

(-3s+s)+11=(-s-9)+s

Simplify the arithmetic:

-2s+11=(-s-9)+s

Group like terms:

-2s+11=(-s+s)-9

Simplify the arithmetic:

-2s+11=-9

Subtract from both sides:

(-2s+11)-11=-9-11

Simplify the arithmetic:

-2s=-9-11

Simplify the arithmetic:

-2s=-20

Divide both sides by :

(-2s)-2=-20-2

Cancel out the negatives:

2s2=-20-2

Simplify the fraction:

s=-20-2

Cancel out the negatives:

s=202

Find the greatest common factor of the numerator and denominator:

s=(10·2)(1·2)

Factor out and cancel the greatest common factor:

s=10

14 additional steps

(-3s+11)=-(-s-9)

Expand the parentheses:

(-3s+11)=s+9

Subtract from both sides:

(-3s+11)-s=(s+9)-s

Group like terms:

(-3s-s)+11=(s+9)-s

Simplify the arithmetic:

-4s+11=(s+9)-s

Group like terms:

-4s+11=(s-s)+9

Simplify the arithmetic:

-4s+11=9

Subtract from both sides:

(-4s+11)-11=9-11

Simplify the arithmetic:

-4s=9-11

Simplify the arithmetic:

-4s=-2

Divide both sides by :

(-4s)-4=-2-4

Cancel out the negatives:

4s4=-2-4

Simplify the fraction:

s=-2-4

Cancel out the negatives:

s=24

Find the greatest common factor of the numerator and denominator:

s=(1·2)(2·2)

Factor out and cancel the greatest common factor:

s=12

3. List the solutions

s=10,12
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3s+11|
y=|s9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.