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Solution - Absolute value equations

Exact form: k=-58,52
k=-\frac{5}{8} , \frac{5}{2}
Mixed number form: k=-58,212
k=-\frac{5}{8} , 2\frac{1}{2}
Decimal form: k=0.625,2.5
k=-0.625 , 2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3k5|=|5k|
without the absolute value bars:

|x|=|y||3k5|=|5k|
x=+y(3k5)=(5k)
x=y(3k5)=(5k)
+x=y(3k5)=(5k)
x=y(3k5)=(5k)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3k5|=|5k|
x=+y , +x=y(3k5)=(5k)
x=y , x=y(3k5)=(5k)

2. Solve the two equations for k

10 additional steps

(-3k-5)=5k

Subtract from both sides:

(-3k-5)-5k=(5k)-5k

Group like terms:

(-3k-5k)-5=(5k)-5k

Simplify the arithmetic:

-8k-5=(5k)-5k

Simplify the arithmetic:

8k5=0

Add to both sides:

(-8k-5)+5=0+5

Simplify the arithmetic:

8k=0+5

Simplify the arithmetic:

8k=5

Divide both sides by :

(-8k)-8=5-8

Cancel out the negatives:

8k8=5-8

Simplify the fraction:

k=5-8

Move the negative sign from the denominator to the numerator:

k=-58

7 additional steps

(-3k-5)=-5k

Add to both sides:

(-3k-5)+5=(-5k)+5

Simplify the arithmetic:

-3k=(-5k)+5

Add to both sides:

(-3k)+5k=((-5k)+5)+5k

Simplify the arithmetic:

2k=((-5k)+5)+5k

Group like terms:

2k=(-5k+5k)+5

Simplify the arithmetic:

2k=5

Divide both sides by :

(2k)2=52

Simplify the fraction:

k=52

3. List the solutions

k=-58,52
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3k5|
y=|5k|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.