Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: k=2,4
k=2 , -4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3k+3|=|2k7|
without the absolute value bars:

|x|=|y||3k+3|=|2k7|
x=+y(3k+3)=(2k7)
x=y(3k+3)=(2k7)
+x=y(3k+3)=(2k7)
x=y(3k+3)=(2k7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3k+3|=|2k7|
x=+y , +x=y(3k+3)=(2k7)
x=y , x=y(3k+3)=(2k7)

2. Solve the two equations for k

13 additional steps

(-3k+3)=(2k-7)

Subtract from both sides:

(-3k+3)-2k=(2k-7)-2k

Group like terms:

(-3k-2k)+3=(2k-7)-2k

Simplify the arithmetic:

-5k+3=(2k-7)-2k

Group like terms:

-5k+3=(2k-2k)-7

Simplify the arithmetic:

5k+3=7

Subtract from both sides:

(-5k+3)-3=-7-3

Simplify the arithmetic:

5k=73

Simplify the arithmetic:

5k=10

Divide both sides by :

(-5k)-5=-10-5

Cancel out the negatives:

5k5=-10-5

Simplify the fraction:

k=-10-5

Cancel out the negatives:

k=105

Find the greatest common factor of the numerator and denominator:

k=(2·5)(1·5)

Factor out and cancel the greatest common factor:

k=2

11 additional steps

(-3k+3)=-(2k-7)

Expand the parentheses:

(-3k+3)=-2k+7

Add to both sides:

(-3k+3)+2k=(-2k+7)+2k

Group like terms:

(-3k+2k)+3=(-2k+7)+2k

Simplify the arithmetic:

-k+3=(-2k+7)+2k

Group like terms:

-k+3=(-2k+2k)+7

Simplify the arithmetic:

k+3=7

Subtract from both sides:

(-k+3)-3=7-3

Simplify the arithmetic:

k=73

Simplify the arithmetic:

k=4

Multiply both sides by :

-k·-1=4·-1

Remove the one(s):

k=4·-1

Simplify the arithmetic:

k=4

3. List the solutions

k=2,4
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3k+3|
y=|2k7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.