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Solution - Absolute value equations

Exact form: x=-32
x=-\frac{3}{2}
Mixed number form: x=-112
x=-1\frac{1}{2}
Decimal form: x=1.5
x=-1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x3|=|3x+6|
without the absolute value bars:

|x|=|y||3x3|=|3x+6|
x=+y(3x3)=(3x+6)
x=y(3x3)=(3x+6)
+x=y(3x3)=(3x+6)
x=y(3x3)=(3x+6)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x3|=|3x+6|
x=+y , +x=y(3x3)=(3x+6)
x=y , x=y(3x3)=(3x+6)

2. Solve the two equations for x

13 additional steps

(-3x-3)=(3x+6)

Subtract from both sides:

(-3x-3)-3x=(3x+6)-3x

Group like terms:

(-3x-3x)-3=(3x+6)-3x

Simplify the arithmetic:

-6x-3=(3x+6)-3x

Group like terms:

-6x-3=(3x-3x)+6

Simplify the arithmetic:

6x3=6

Add to both sides:

(-6x-3)+3=6+3

Simplify the arithmetic:

6x=6+3

Simplify the arithmetic:

6x=9

Divide both sides by :

(-6x)-6=9-6

Cancel out the negatives:

6x6=9-6

Simplify the fraction:

x=9-6

Move the negative sign from the denominator to the numerator:

x=-96

Find the greatest common factor of the numerator and denominator:

x=(-3·3)(2·3)

Factor out and cancel the greatest common factor:

x=-32

6 additional steps

(-3x-3)=-(3x+6)

Expand the parentheses:

(-3x-3)=-3x-6

Add to both sides:

(-3x-3)+3x=(-3x-6)+3x

Group like terms:

(-3x+3x)-3=(-3x-6)+3x

Simplify the arithmetic:

-3=(-3x-6)+3x

Group like terms:

-3=(-3x+3x)-6

Simplify the arithmetic:

3=6

The statement is false:

3=6

The equation is false so it has no solution.

3. List the solutions

x=-32
(1 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3x3|
y=|3x+6|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.