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Solution - Absolute value equations

Exact form: x=4,-25
x=4 , -\frac{2}{5}
Decimal form: x=4,0.4
x=4 , -0.4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x3|+|3x1|=0

Add |3x1| to both sides of the equation:

|2x3|+|3x1||3x1|=|3x1|

Simplify the arithmetic

|2x3|=|3x1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x3|=|3x1|
without the absolute value bars:

|x|=|y||2x3|=|3x1|
x=+y(2x3)=(3x1)
x=y(2x3)=(3x1)
+x=y(2x3)=(3x1)
x=y(2x3)=(3x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x3|=|3x1|
x=+y , +x=y(2x3)=(3x1)
x=y , x=y(2x3)=(3x1)

3. Solve the two equations for x

8 additional steps

(-2x-3)=-(3x-1)

Expand the parentheses:

(-2x-3)=-3x+1

Add to both sides:

(-2x-3)+3x=(-3x+1)+3x

Group like terms:

(-2x+3x)-3=(-3x+1)+3x

Simplify the arithmetic:

x-3=(-3x+1)+3x

Group like terms:

x-3=(-3x+3x)+1

Simplify the arithmetic:

x3=1

Add to both sides:

(x-3)+3=1+3

Simplify the arithmetic:

x=1+3

Simplify the arithmetic:

x=4

12 additional steps

(-2x-3)=-(-(3x-1))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(-2x-3)=3x-1

Subtract from both sides:

(-2x-3)-3x=(3x-1)-3x

Group like terms:

(-2x-3x)-3=(3x-1)-3x

Simplify the arithmetic:

-5x-3=(3x-1)-3x

Group like terms:

-5x-3=(3x-3x)-1

Simplify the arithmetic:

5x3=1

Add to both sides:

(-5x-3)+3=-1+3

Simplify the arithmetic:

5x=1+3

Simplify the arithmetic:

5x=2

Divide both sides by :

(-5x)-5=2-5

Cancel out the negatives:

5x5=2-5

Simplify the fraction:

x=2-5

Move the negative sign from the denominator to the numerator:

x=-25

4. List the solutions

x=4,-25
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|2x3|
y=|3x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.