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Solution - Absolute value equations

Exact form: x=14,-3
x=\frac{1}{4} , -3
Decimal form: x=0.25,3
x=0.25 , -3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+7|=|6x+5|
without the absolute value bars:

|x|=|y||2x+7|=|6x+5|
x=+y(2x+7)=(6x+5)
x=y(2x+7)=(6x+5)
+x=y(2x+7)=(6x+5)
x=y(2x+7)=(6x+5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+7|=|6x+5|
x=+y , +x=y(2x+7)=(6x+5)
x=y , x=y(2x+7)=(6x+5)

2. Solve the two equations for x

13 additional steps

(-2x+7)=(6x+5)

Subtract from both sides:

(-2x+7)-6x=(6x+5)-6x

Group like terms:

(-2x-6x)+7=(6x+5)-6x

Simplify the arithmetic:

-8x+7=(6x+5)-6x

Group like terms:

-8x+7=(6x-6x)+5

Simplify the arithmetic:

8x+7=5

Subtract from both sides:

(-8x+7)-7=5-7

Simplify the arithmetic:

8x=57

Simplify the arithmetic:

8x=2

Divide both sides by :

(-8x)-8=-2-8

Cancel out the negatives:

8x8=-2-8

Simplify the fraction:

x=-2-8

Cancel out the negatives:

x=28

Find the greatest common factor of the numerator and denominator:

x=(1·2)(4·2)

Factor out and cancel the greatest common factor:

x=14

12 additional steps

(-2x+7)=-(6x+5)

Expand the parentheses:

(-2x+7)=-6x-5

Add to both sides:

(-2x+7)+6x=(-6x-5)+6x

Group like terms:

(-2x+6x)+7=(-6x-5)+6x

Simplify the arithmetic:

4x+7=(-6x-5)+6x

Group like terms:

4x+7=(-6x+6x)-5

Simplify the arithmetic:

4x+7=5

Subtract from both sides:

(4x+7)-7=-5-7

Simplify the arithmetic:

4x=57

Simplify the arithmetic:

4x=12

Divide both sides by :

(4x)4=-124

Simplify the fraction:

x=-124

Find the greatest common factor of the numerator and denominator:

x=(-3·4)(1·4)

Factor out and cancel the greatest common factor:

x=3

3. List the solutions

x=14,-3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+7|
y=|6x+5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.