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Solution - Absolute value equations

Exact form: x=-13,57
x=-\frac{1}{3} , \frac{5}{7}
Decimal form: x=0.333,0.714
x=-0.333 , 0.714

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+3|=|5x+2|
without the absolute value bars:

|x|=|y||2x+3|=|5x+2|
x=+y(2x+3)=(5x+2)
x=y(2x+3)=(5x+2)
+x=y(2x+3)=(5x+2)
x=y(2x+3)=(5x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+3|=|5x+2|
x=+y , +x=y(2x+3)=(5x+2)
x=y , x=y(2x+3)=(5x+2)

2. Solve the two equations for x

9 additional steps

(-2x+3)=(-5x+2)

Add to both sides:

(-2x+3)+5x=(-5x+2)+5x

Group like terms:

(-2x+5x)+3=(-5x+2)+5x

Simplify the arithmetic:

3x+3=(-5x+2)+5x

Group like terms:

3x+3=(-5x+5x)+2

Simplify the arithmetic:

3x+3=2

Subtract from both sides:

(3x+3)-3=2-3

Simplify the arithmetic:

3x=23

Simplify the arithmetic:

3x=1

Divide both sides by :

(3x)3=-13

Simplify the fraction:

x=-13

12 additional steps

(-2x+3)=-(-5x+2)

Expand the parentheses:

(-2x+3)=5x-2

Subtract from both sides:

(-2x+3)-5x=(5x-2)-5x

Group like terms:

(-2x-5x)+3=(5x-2)-5x

Simplify the arithmetic:

-7x+3=(5x-2)-5x

Group like terms:

-7x+3=(5x-5x)-2

Simplify the arithmetic:

7x+3=2

Subtract from both sides:

(-7x+3)-3=-2-3

Simplify the arithmetic:

7x=23

Simplify the arithmetic:

7x=5

Divide both sides by :

(-7x)-7=-5-7

Cancel out the negatives:

7x7=-5-7

Simplify the fraction:

x=-5-7

Cancel out the negatives:

x=57

3. List the solutions

x=-13,57
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+3|
y=|5x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.