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Solution - Absolute value equations

Exact form: x=-12,56
x=-\frac{1}{2} , \frac{5}{6}
Decimal form: x=0.5,0.833
x=-0.5 , 0.833

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+3|=|4x+2|
without the absolute value bars:

|x|=|y||2x+3|=|4x+2|
x=+y(2x+3)=(4x+2)
x=y(2x+3)=(4x+2)
+x=y(2x+3)=(4x+2)
x=y(2x+3)=(4x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+3|=|4x+2|
x=+y , +x=y(2x+3)=(4x+2)
x=y , x=y(2x+3)=(4x+2)

2. Solve the two equations for x

9 additional steps

(-2x+3)=(-4x+2)

Add to both sides:

(-2x+3)+4x=(-4x+2)+4x

Group like terms:

(-2x+4x)+3=(-4x+2)+4x

Simplify the arithmetic:

2x+3=(-4x+2)+4x

Group like terms:

2x+3=(-4x+4x)+2

Simplify the arithmetic:

2x+3=2

Subtract from both sides:

(2x+3)-3=2-3

Simplify the arithmetic:

2x=23

Simplify the arithmetic:

2x=1

Divide both sides by :

(2x)2=-12

Simplify the fraction:

x=-12

12 additional steps

(-2x+3)=-(-4x+2)

Expand the parentheses:

(-2x+3)=4x-2

Subtract from both sides:

(-2x+3)-4x=(4x-2)-4x

Group like terms:

(-2x-4x)+3=(4x-2)-4x

Simplify the arithmetic:

-6x+3=(4x-2)-4x

Group like terms:

-6x+3=(4x-4x)-2

Simplify the arithmetic:

6x+3=2

Subtract from both sides:

(-6x+3)-3=-2-3

Simplify the arithmetic:

6x=23

Simplify the arithmetic:

6x=5

Divide both sides by :

(-6x)-6=-5-6

Cancel out the negatives:

6x6=-5-6

Simplify the fraction:

x=-5-6

Cancel out the negatives:

x=56

3. List the solutions

x=-12,56
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|2x+3|
y=|4x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.