Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=23,-8
x=\frac{2}{3} , -8
Decimal form: x=0.667,8
x=0.667 , -8

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x1|=|4x7|
without the absolute value bars:

|x|=|y||5x1|=|4x7|
x=+y(5x1)=(4x7)
x=y(5x1)=(4x7)
+x=y(5x1)=(4x7)
x=y(5x1)=(4x7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x1|=|4x7|
x=+y , +x=y(5x1)=(4x7)
x=y , x=y(5x1)=(4x7)

2. Solve the two equations for x

13 additional steps

(-5x-1)=(4x-7)

Subtract from both sides:

(-5x-1)-4x=(4x-7)-4x

Group like terms:

(-5x-4x)-1=(4x-7)-4x

Simplify the arithmetic:

-9x-1=(4x-7)-4x

Group like terms:

-9x-1=(4x-4x)-7

Simplify the arithmetic:

9x1=7

Add to both sides:

(-9x-1)+1=-7+1

Simplify the arithmetic:

9x=7+1

Simplify the arithmetic:

9x=6

Divide both sides by :

(-9x)-9=-6-9

Cancel out the negatives:

9x9=-6-9

Simplify the fraction:

x=-6-9

Cancel out the negatives:

x=69

Find the greatest common factor of the numerator and denominator:

x=(2·3)(3·3)

Factor out and cancel the greatest common factor:

x=23

11 additional steps

(-5x-1)=-(4x-7)

Expand the parentheses:

(-5x-1)=-4x+7

Add to both sides:

(-5x-1)+4x=(-4x+7)+4x

Group like terms:

(-5x+4x)-1=(-4x+7)+4x

Simplify the arithmetic:

-x-1=(-4x+7)+4x

Group like terms:

-x-1=(-4x+4x)+7

Simplify the arithmetic:

x1=7

Add to both sides:

(-x-1)+1=7+1

Simplify the arithmetic:

x=7+1

Simplify the arithmetic:

x=8

Multiply both sides by :

-x·-1=8·-1

Remove the one(s):

x=8·-1

Simplify the arithmetic:

x=8

3. List the solutions

x=23,-8
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x1|
y=|4x7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.