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Solution - Absolute value equations

Exact form: x=-8,65
x=-8 , \frac{6}{5}
Mixed number form: x=-8,115
x=-8 , 1\frac{1}{5}
Decimal form: x=8,1.2
x=-8 , 1.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|3x1|+|2x7|=0

Add |2x7| to both sides of the equation:

|3x1|+|2x7||2x7|=|2x7|

Simplify the arithmetic

|3x1|=|2x7|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3x1|=|2x7|
without the absolute value bars:

|x|=|y||3x1|=|2x7|
x=+y(3x1)=(2x7)
x=y(3x1)=(2x7)
+x=y(3x1)=(2x7)
x=y(3x1)=(2x7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3x1|=|2x7|
x=+y , +x=y(3x1)=(2x7)
x=y , x=y(3x1)=(2x7)

3. Solve the two equations for x

11 additional steps

(-3x-1)=-(2x-7)

Expand the parentheses:

(-3x-1)=-2x+7

Add to both sides:

(-3x-1)+2x=(-2x+7)+2x

Group like terms:

(-3x+2x)-1=(-2x+7)+2x

Simplify the arithmetic:

-x-1=(-2x+7)+2x

Group like terms:

-x-1=(-2x+2x)+7

Simplify the arithmetic:

x1=7

Add to both sides:

(-x-1)+1=7+1

Simplify the arithmetic:

x=7+1

Simplify the arithmetic:

x=8

Multiply both sides by :

-x·-1=8·-1

Remove the one(s):

x=8·-1

Simplify the arithmetic:

x=8

12 additional steps

(-3x-1)=-(-(2x-7))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(-3x-1)=2x-7

Subtract from both sides:

(-3x-1)-2x=(2x-7)-2x

Group like terms:

(-3x-2x)-1=(2x-7)-2x

Simplify the arithmetic:

-5x-1=(2x-7)-2x

Group like terms:

-5x-1=(2x-2x)-7

Simplify the arithmetic:

5x1=7

Add to both sides:

(-5x-1)+1=-7+1

Simplify the arithmetic:

5x=7+1

Simplify the arithmetic:

5x=6

Divide both sides by :

(-5x)-5=-6-5

Cancel out the negatives:

5x5=-6-5

Simplify the fraction:

x=-6-5

Cancel out the negatives:

x=65

4. List the solutions

x=-8,65
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|3x1|
y=|2x7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.