Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: v=65,-8
v=\frac{6}{5} , -8
Mixed number form: v=115,-8
v=1\frac{1}{5} , -8
Decimal form: v=1.2,8
v=1.2 , -8

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|3v1|=|2v7|
without the absolute value bars:

|x|=|y||3v1|=|2v7|
x=+y(3v1)=(2v7)
x=y(3v1)=(2v7)
+x=y(3v1)=(2v7)
x=y(3v1)=(2v7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||3v1|=|2v7|
x=+y , +x=y(3v1)=(2v7)
x=y , x=y(3v1)=(2v7)

2. Solve the two equations for v

11 additional steps

(-3v-1)=(2v-7)

Subtract from both sides:

(-3v-1)-2v=(2v-7)-2v

Group like terms:

(-3v-2v)-1=(2v-7)-2v

Simplify the arithmetic:

-5v-1=(2v-7)-2v

Group like terms:

-5v-1=(2v-2v)-7

Simplify the arithmetic:

5v1=7

Add to both sides:

(-5v-1)+1=-7+1

Simplify the arithmetic:

5v=7+1

Simplify the arithmetic:

5v=6

Divide both sides by :

(-5v)-5=-6-5

Cancel out the negatives:

5v5=-6-5

Simplify the fraction:

v=-6-5

Cancel out the negatives:

v=65

11 additional steps

(-3v-1)=-(2v-7)

Expand the parentheses:

(-3v-1)=-2v+7

Add to both sides:

(-3v-1)+2v=(-2v+7)+2v

Group like terms:

(-3v+2v)-1=(-2v+7)+2v

Simplify the arithmetic:

-v-1=(-2v+7)+2v

Group like terms:

-v-1=(-2v+2v)+7

Simplify the arithmetic:

v1=7

Add to both sides:

(-v-1)+1=7+1

Simplify the arithmetic:

v=7+1

Simplify the arithmetic:

v=8

Multiply both sides by :

-v·-1=8·-1

Remove the one(s):

v=8·-1

Simplify the arithmetic:

v=8

3. List the solutions

v=65,-8
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|3v1|
y=|2v7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.