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Solution - Absolute value equations

Exact form: =-13,-16
=-\frac{1}{3} , -\frac{1}{6}
Decimal form: =0.333,0.167
=-0.333 , -0.167

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|1|=|12x+3|
without the absolute value bars:

|x|=|y||1|=|12x+3|
x=+y(1)=(12x+3)
x=y(1)=(12x+3)
+x=y(1)=(12x+3)
x=y(1)=(12x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||1|=|12x+3|
x=+y , +x=y(1)=(12x+3)
x=y , x=y(1)=(12x+3)

2. Solve the two equations for

7 additional steps

-1=(12x+3)

Swap sides:

(12x+3)=-1

Subtract from both sides:

(12x+3)-3=-1-3

Simplify the arithmetic:

12x=13

Simplify the arithmetic:

12x=4

Divide both sides by :

(12x)12=-412

Simplify the fraction:

x=-412

Find the greatest common factor of the numerator and denominator:

x=(-1·4)(3·4)

Factor out and cancel the greatest common factor:

x=-13

10 additional steps

-1=-(12x+3)

Expand the parentheses:

1=12x3

Swap sides:

12x3=1

Add to both sides:

(-12x-3)+3=-1+3

Simplify the arithmetic:

12x=1+3

Simplify the arithmetic:

12x=2

Divide both sides by :

(-12x)-12=2-12

Cancel out the negatives:

12x12=2-12

Simplify the fraction:

x=2-12

Move the negative sign from the denominator to the numerator:

x=-212

Find the greatest common factor of the numerator and denominator:

x=(-1·2)(6·2)

Factor out and cancel the greatest common factor:

x=-16

3. List the solutions

=-13,-16
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|1|
y=|12x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.